What are the solutions to the equation solvefor x,z=x^2+4y^2 ?

The solutions to the equation solvefor x,z=x^2+4y^2 are x=sqrt(z-4y^2),x=-sqrt(z-4y^2)

Find the zeros of solvefor x,z=x^2+4y^2

The zeros of solvefor x,z=x^2+4y^2 are x=sqrt(z-4y^2),x=-sqrt(z-4y^2)

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solve for

x, z = x^{2} + 4 y^{2}

x = z - 4 y^{2}, x = - z - 4 y^{2}

Solution steps

z = x^{2} + 4 y^{2}

Switch sides

x^{2} + 4 y^{2} = z

Move

4 y^{2}

to the right side

x^{2} = z - 4 y^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = z - 4 y^{2}, x = - z - 4 y^{2}

x, y = x^{2} - 3 x + 2

\frac{1}{2} x^{2} - 5 = 5

r, S = 2 π r h + 2 π r^{2}

A (x) = - x (x - 80)

(x + 2)^{2} - 16 = 0

What are the solutions to the equation solvefor x,z=x^2+4y^2 ?
The solutions to the equation solvefor x,z=x^2+4y^2 are x=sqrt(z-4y^2),x=-sqrt(z-4y^2)
Find the zeros of solvefor x,z=x^2+4y^2
The zeros of solvefor x,z=x^2+4y^2 are x=sqrt(z-4y^2),x=-sqrt(z-4y^2)