What are the solutions to the equation (x+2)^2-16=0 ?

The solutions to the equation (x+2)^2-16=0 are x=2,x=-6

Find the zeros of (x+2)^2-16=0

The zeros of (x+2)^2-16=0 are x=2,x=-6

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(x + 2)^{2} - 16 = 0

x = 2, x = - 6

Solution steps

(x + 2)^{2} - 16 = 0

Move

16

to the right side

(x + 2)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 16 : x = 2

Solve

x + 2 = - 16 : x = - 6

The solutions to the quadratic equation are:

x = 2, x = - 6

3^{2} = 1^{2} + x^{2}

3 y^{2} - 3 = 0

x^{2} - 2 x - 15 = 0

x^{2} - 4 x - 12 = 0

15 x^{2} + 19 x - 10 = 0

What are the solutions to the equation (x+2)^2-16=0 ?
The solutions to the equation (x+2)^2-16=0 are x=2,x=-6
Find the zeros of (x+2)^2-16=0
The zeros of (x+2)^2-16=0 are x=2,x=-6