What are the solutions to the equation 3y^2-3=0 ?

The solutions to the equation 3y^2-3=0 are y=1,y=-1

Find the zeros of 3y^2-3=0

The zeros of 3y^2-3=0 are y=1,y=-1

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3 y^{2} - 3 = 0

y = 1, y = - 1

Solution steps

3 y^{2} - 3 = 0

Move

3

to the right side

3 y^{2} = 3

Divide both sides by

3

y^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 1, y = - 1

1 = 1

- 1 = - 1

y = 1, y = - 1

x^{2} - 2 x - 15 = 0

x^{2} - 4 x - 12 = 0

15 x^{2} + 19 x - 10 = 0

4 (x - 9)^{2} + 25 = 45

(x + 9)^{2} = - 9

What are the solutions to the equation 3y^2-3=0 ?
The solutions to the equation 3y^2-3=0 are y=1,y=-1
Find the zeros of 3y^2-3=0
The zeros of 3y^2-3=0 are y=1,y=-1