What are the solutions to the equation x^2+4x+4=2 ?

The solutions to the equation x^2+4x+4=2 are x=-2+sqrt(2),x=-2-sqrt(2)

Find the zeros of x^2+4x+4=2

The zeros of x^2+4x+4=2 are x=-2+sqrt(2),x=-2-sqrt(2)

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x^{2} + 4 x + 4 = 2

x = - 2 + 2, x = - 2 - 2

Decimal Notation

x = - 0.58578 \dots, x = - 3.41421 \dots

Solution steps

x^{2} + 4 x + 4 = 2

Move

2

to the left side

x^{2} + 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 2 = 22

x_{1, 2} = \frac{- 4 \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 2}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 2}{2 \cdot 1}

x = \frac{- 4 + 2 2}{2 \cdot 1} : - 2 + 2

x = \frac{- 4 - 2 2}{2 \cdot 1} : - 2 - 2

The solutions to the quadratic equation are:

x = - 2 + 2, x = - 2 - 2

x^{2} + 2 x + 10

2 x (x + 3) + (x - 3)^{2} = 9

(\frac{1}{2})^{2} + y^{2} = 1

x, 4 x^{2} + 4 y^{2} + 28 x - 8 y + 53 = 0

- 2 (x + 2)^{2} = 5

What are the solutions to the equation x^2+4x+4=2 ?
The solutions to the equation x^2+4x+4=2 are x=-2+sqrt(2),x=-2-sqrt(2)
Find the zeros of x^2+4x+4=2
The zeros of x^2+4x+4=2 are x=-2+sqrt(2),x=-2-sqrt(2)