What are the solutions to the equation 5v^2+18v+12=-3 ?

The solutions to the equation 5v^2+18v+12=-3 are v=(-9+sqrt(6))/5 ,v=-(9+sqrt(6))/5

Find the zeros of 5v^2+18v+12=-3

The zeros of 5v^2+18v+12=-3 are v=(-9+sqrt(6))/5 ,v=-(9+sqrt(6))/5

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5 v^{2} + 18 v + 12 = - 3

v = \frac{- 9 + 6}{5}, v = - \frac{9 + 6}{5}

Decimal Notation

v = - 1.31010 \dots, v = - 2.28989 \dots

Solution steps

5 v^{2} + 18 v + 12 = - 3

Move

3

to the left side

5 v^{2} + 18 v + 15 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 5 \cdot 15}{2 \cdot 5}

1 8^{2} - 4 \cdot 5 \cdot 15 = 26

v_{1, 2} = \frac{- 18 \pm 2 6}{2 \cdot 5}

Separate the solutions

v_{1} = \frac{- 18 + 2 6}{2 \cdot 5}, v_{2} = \frac{- 18 - 2 6}{2 \cdot 5}

v = \frac{- 18 + 2 6}{2 \cdot 5} : \frac{- 9 + 6}{5}

v = \frac{- 18 - 2 6}{2 \cdot 5} : - \frac{9 + 6}{5}

The solutions to the quadratic equation are:

v = \frac{- 9 + 6}{5}, v = - \frac{9 + 6}{5}

12 x^{2} - 276 x + 1080 = 0

s, 12 x^{2} - 8 x s + s^{2} = 0

2 a^{2} + 8 a + 10 = a^{2}

(4 q + 5) (q - 5) = 0

4 y^{2} - 12 = 0

What are the solutions to the equation 5v^2+18v+12=-3 ?
The solutions to the equation 5v^2+18v+12=-3 are v=(-9+sqrt(6))/5 ,v=-(9+sqrt(6))/5
Find the zeros of 5v^2+18v+12=-3
The zeros of 5v^2+18v+12=-3 are v=(-9+sqrt(6))/5 ,v=-(9+sqrt(6))/5