What are the solutions to the equation solvefor y,x^2+y^2=4 ?

The solutions to the equation solvefor y,x^2+y^2=4 are y=sqrt(4-x^2),y=-sqrt(4-x^2)

Find the zeros of solvefor y,x^2+y^2=4

The zeros of solvefor y,x^2+y^2=4 are y=sqrt(4-x^2),y=-sqrt(4-x^2)

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solve for

y, x^{2} + y^{2} = 4

y = 4 - x^{2}, y = - 4 - x^{2}

Solution steps

x^{2} + y^{2} = 4

Move

x^{2}

to the right side

y^{2} = 4 - x^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 4 - x^{2}, y = - 4 - x^{2}

- x^{2} - x - 2 = 0

(x^{2} + 2 x + 2) = 0

x^{2} + 14 x = 32

3 x^{2} - 4 x = 1

x^{2} - 54 = 0

What are the solutions to the equation solvefor y,x^2+y^2=4 ?
The solutions to the equation solvefor y,x^2+y^2=4 are y=sqrt(4-x^2),y=-sqrt(4-x^2)
Find the zeros of solvefor y,x^2+y^2=4
The zeros of solvefor y,x^2+y^2=4 are y=sqrt(4-x^2),y=-sqrt(4-x^2)