What are the solutions to the equation (x^2+2x+2)=0 ?

The solutions to the equation (x^2+2x+2)=0 are x=-1+i,x=-1-i

Find the zeros of (x^2+2x+2)=0

The zeros of (x^2+2x+2)=0 are x=-1+i,x=-1-i

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(x^{2} + 2 x + 2) = 0

x = - 1 + i, x = - 1 - i

Solution steps

(x^{2} + 2 x + 2) = 0

Refine

x^{2} + 2 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 2 : 2 i

x_{1, 2} = \frac{- 2 \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 i}{2 \cdot 1}

x = \frac{- 2 + 2 i}{2 \cdot 1} : - 1 + i

x = \frac{- 2 - 2 i}{2 \cdot 1} : - 1 - i

The solutions to the quadratic equation are:

x = - 1 + i, x = - 1 - i

x^{2} + 14 x = 32

3 x^{2} - 4 x = 1

x^{2} - 54 = 0

- 2 x^{2} - x = 0

m^{2} - 2 m - 15 = 0

What are the solutions to the equation (x^2+2x+2)=0 ?
The solutions to the equation (x^2+2x+2)=0 are x=-1+i,x=-1-i
Find the zeros of (x^2+2x+2)=0
The zeros of (x^2+2x+2)=0 are x=-1+i,x=-1-i