What are the solutions to the equation x^2-10x-13=0 ?

The solutions to the equation x^2-10x-13=0 are x=5+sqrt(38),x=5-sqrt(38)

Find the zeros of x^2-10x-13=0

The zeros of x^2-10x-13=0 are x=5+sqrt(38),x=5-sqrt(38)

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x^{2} - 10 x - 13 = 0

x = 5 + 38, x = 5 - 38

Decimal Notation

x = 11.16441 \dots, x = - 1.16441 \dots

Solution steps

x^{2} - 10 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 13 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 13) = 238

x_{1, 2} = \frac{- ( - 10 ) \pm 2 38}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 38}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 38}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 38}{2 \cdot 1} : 5 + 38

x = \frac{- ( - 10 ) - 2 38}{2 \cdot 1} : 5 - 38

The solutions to the quadratic equation are:

x = 5 + 38, x = 5 - 38

5^{2} + 5^{2} = c^{2}

x^{2} + 6 x + 24 = 0

x^{2} + 26 x = 27

(5 x - 3)^{2} = 64

a^{2} - 8 a - 6 = 0

What are the solutions to the equation x^2-10x-13=0 ?
The solutions to the equation x^2-10x-13=0 are x=5+sqrt(38),x=5-sqrt(38)
Find the zeros of x^2-10x-13=0
The zeros of x^2-10x-13=0 are x=5+sqrt(38),x=5-sqrt(38)