What are the solutions to the equation m^2+5m=2m^2 ?

The solutions to the equation m^2+5m=2m^2 are m=0,m=5

Find the zeros of m^2+5m=2m^2

The zeros of m^2+5m=2m^2 are m=0,m=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

m^{2} + 5 m = 2 m^{2}

m = 0, m = 5

Solution steps

m^{2} + 5 m = 2 m^{2}

Move

2 m^{2}

to the left side

- m^{2} + 5 m = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

5^{2} - 4 (- 1) \cdot 0 = 5

m_{1, 2} = \frac{- 5 \pm 5}{2 ( - 1 )}

Separate the solutions

m_{1} = \frac{- 5 + 5}{2 ( - 1 )}, m_{2} = \frac{- 5 - 5}{2 ( - 1 )}

m = \frac{- 5 + 5}{2 ( - 1 )} : 0

m = \frac{- 5 - 5}{2 ( - 1 )} : 5

The solutions to the quadratic equation are:

m = 0, m = 5

4 x^{2} - 2 x = 3

x^{2} + 2 x + 1 = 3 x + 3

x^{2} - 5 x + 6 = 0

5 d^{2} + 15 d + 5 = - 6

2 x^{2} + 4 x - 5

What are the solutions to the equation m^2+5m=2m^2 ?
The solutions to the equation m^2+5m=2m^2 are m=0,m=5
Find the zeros of m^2+5m=2m^2
The zeros of m^2+5m=2m^2 are m=0,m=5