What are the solutions to the equation x^2-15x+44=0 ?

The solutions to the equation x^2-15x+44=0 are x=11,x=4

Find the zeros of x^2-15x+44=0

The zeros of x^2-15x+44=0 are x=11,x=4

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x^{2} - 15 x + 44 = 0

x = 11, x = 4

Solution steps

x^{2} - 15 x + 44 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 44}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 44 = 7

x_{1, 2} = \frac{- ( - 15 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 7}{2 \cdot 1}

x = \frac{- ( - 15 ) + 7}{2 \cdot 1} : 11

x = \frac{- ( - 15 ) - 7}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

x = 11, x = 4

x, x^{2} + x y + 2 y^{2} = 28

3 (4 x - 6)^{2} - 21 = - 9

x^{2} + 1 = 4 x^{2}

- 15 x = 45 x^{2}

x, 5 x^{2} + 5 y^{2} + 10 x - 10 y + 20 = 0

What are the solutions to the equation x^2-15x+44=0 ?
The solutions to the equation x^2-15x+44=0 are x=11,x=4
Find the zeros of x^2-15x+44=0
The zeros of x^2-15x+44=0 are x=11,x=4