What are the solutions to the equation 3m^2-5m=4 ?

The solutions to the equation 3m^2-5m=4 are m=(5+sqrt(73))/6 ,m=(5-sqrt(73))/6

Find the zeros of 3m^2-5m=4

The zeros of 3m^2-5m=4 are m=(5+sqrt(73))/6 ,m=(5-sqrt(73))/6

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3 m^{2} - 5 m = 4

m = \frac{5 + 73}{6}, m = \frac{5 - 73}{6}

Decimal Notation

m = 2.25733 \dots, m = - 0.59066 \dots

Solution steps

3 m^{2} - 5 m = 4

Move

4

to the left side

3 m^{2} - 5 m - 4 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 4) = 73

m_{1, 2} = \frac{- ( - 5 ) \pm 73}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- ( - 5 ) + 73}{2 \cdot 3}, m_{2} = \frac{- ( - 5 ) - 73}{2 \cdot 3}

m = \frac{- ( - 5 ) + 73}{2 \cdot 3} : \frac{5 + 73}{6}

m = \frac{- ( - 5 ) - 73}{2 \cdot 3} : \frac{5 - 73}{6}

The solutions to the quadratic equation are:

m = \frac{5 + 73}{6}, m = \frac{5 - 73}{6}

x^{2} + x + 14 = 0

6^{2} + 3^{2} = x^{2}

s^{2} + 10 s + 100 = 0

x^{2} + 2 x - 4

x^{2} + 2 x + 3

What are the solutions to the equation 3m^2-5m=4 ?
The solutions to the equation 3m^2-5m=4 are m=(5+sqrt(73))/6 ,m=(5-sqrt(73))/6
Find the zeros of 3m^2-5m=4
The zeros of 3m^2-5m=4 are m=(5+sqrt(73))/6 ,m=(5-sqrt(73))/6