What are the solutions to the equation x^2=sqrt(225)+(sqrt(81))+(2^3+sqrt(16)) ?

The solutions to the equation x^2=sqrt(225)+(sqrt(81))+(2^3+sqrt(16)) are x=6,x=-6

Find the zeros of x^2=sqrt(225)+(sqrt(81))+(2^3+sqrt(16))

The zeros of x^2=sqrt(225)+(sqrt(81))+(2^3+sqrt(16)) are x=6,x=-6

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x^{2} = 225 + (81) + (2^{3} + 16)

x = 6, x = - 6

Solution steps

x^{2} = 225 + (81) + (2^{3} + 16)

Simplify

225 + (81) + (2^{3} + 16) : 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 36, x = - 36

36 = 6

- 36 = - 6

x = 6, x = - 6

- 5 x^{2} - 100 x - 320 = 0

3 x - 2 x^{2} = 7

2 d^{2} + 11 d + 20 = d^{2}

6 x^{2} - 8 x = - 3

6 (x - 1)^{2} + 15 = 105

What are the solutions to the equation x^2=sqrt(225)+(sqrt(81))+(2^3+sqrt(16)) ?
The solutions to the equation x^2=sqrt(225)+(sqrt(81))+(2^3+sqrt(16)) are x=6,x=-6
Find the zeros of x^2=sqrt(225)+(sqrt(81))+(2^3+sqrt(16))
The zeros of x^2=sqrt(225)+(sqrt(81))+(2^3+sqrt(16)) are x=6,x=-6