What are the solutions to the equation -20=8x-4x^2-3 ?

The solutions to the equation -20=8x-4x^2-3 are x=-(-2+sqrt(21))/2 ,x=(2+sqrt(21))/2

Find the zeros of -20=8x-4x^2-3

The zeros of -20=8x-4x^2-3 are x=-(-2+sqrt(21))/2 ,x=(2+sqrt(21))/2

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- 20 = 8 x - 4 x^{2} - 3

x = - \frac{- 2 + 21}{2}, x = \frac{2 + 21}{2}

Decimal Notation

x = - 1.29128 \dots, x = 3.29128 \dots

Solution steps

- 20 = 8 x - 4 x^{2} - 3

Switch sides

8 x - 4 x^{2} - 3 = - 20

Move

20

to the left side

- 4 x^{2} + 8 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 4 ) \cdot 17}{2 ( - 4 )}

8^{2} - 4 (- 4) \cdot 17 = 421

x_{1, 2} = \frac{- 8 \pm 4 21}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 8 + 4 21}{2 ( - 4 )}, x_{2} = \frac{- 8 - 4 21}{2 ( - 4 )}

x = \frac{- 8 + 4 21}{2 ( - 4 )} : - \frac{- 2 + 21}{2}

x = \frac{- 8 - 4 21}{2 ( - 4 )} : \frac{2 + 21}{2}

The solutions to the quadratic equation are:

x = - \frac{- 2 + 21}{2}, x = \frac{2 + 21}{2}

x^{2} + 6 x = - 15

r^{2} + 2 r - 20 = - 3

x^{2} - 12 x - 8 = 0

12 x^{2} - 72 x = 0

x^{2} + 6 x - 7

What are the solutions to the equation -20=8x-4x^2-3 ?
The solutions to the equation -20=8x-4x^2-3 are x=-(-2+sqrt(21))/2 ,x=(2+sqrt(21))/2
Find the zeros of -20=8x-4x^2-3
The zeros of -20=8x-4x^2-3 are x=-(-2+sqrt(21))/2 ,x=(2+sqrt(21))/2