What are the solutions to the equation 9x^2+2x+1=0 ?

The solutions to the equation 9x^2+2x+1=0 are x=-1/9+i(2sqrt(2))/9 ,x=-1/9-i(2sqrt(2))/9

Find the zeros of 9x^2+2x+1=0

The zeros of 9x^2+2x+1=0 are x=-1/9+i(2sqrt(2))/9 ,x=-1/9-i(2sqrt(2))/9

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9 x^{2} + 2 x + 1 = 0

x = - \frac{1}{9} + i \frac{2 2}{9}, x = - \frac{1}{9} - i \frac{2 2}{9}

Solution steps

9 x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

Simplify

2^{2} - 4 \cdot 9 \cdot 1 : 42 i

x_{1, 2} = \frac{- 2 \pm 4 2 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 2 + 4 2 i}{2 \cdot 9}, x_{2} = \frac{- 2 - 4 2 i}{2 \cdot 9}

x = \frac{- 2 + 4 2 i}{2 \cdot 9} : - \frac{1}{9} + i \frac{2 2}{9}

x = \frac{- 2 - 4 2 i}{2 \cdot 9} : - \frac{1}{9} - i \frac{2 2}{9}

The solutions to the quadratic equation are:

x = - \frac{1}{9} + i \frac{2 2}{9}, x = - \frac{1}{9} - i \frac{2 2}{9}

x^{2} + 16 x - 7 = 0

(x + 3) (x + 1) = 4 x + 7

r^{2} - 8 r - 22 = 6

a x^{2} = 0

3 x^{2} + 5 = x^{2} - 2

What are the solutions to the equation 9x^2+2x+1=0 ?
The solutions to the equation 9x^2+2x+1=0 are x=-1/9+i(2sqrt(2))/9 ,x=-1/9-i(2sqrt(2))/9
Find the zeros of 9x^2+2x+1=0
The zeros of 9x^2+2x+1=0 are x=-1/9+i(2sqrt(2))/9 ,x=-1/9-i(2sqrt(2))/9