What are the solutions to the equation r^2-8r-22=6 ?

The solutions to the equation r^2-8r-22=6 are r=2(2+sqrt(11)),r=2(2-sqrt(11))

Find the zeros of r^2-8r-22=6

The zeros of r^2-8r-22=6 are r=2(2+sqrt(11)),r=2(2-sqrt(11))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{2} - 8 r - 22 = 6

r = 2 (2 + 11), r = 2 (2 - 11)

Decimal Notation

r = 10.63324 \dots, r = - 2.63324 \dots

Solution steps

r^{2} - 8 r - 22 = 6

Move

6

to the left side

r^{2} - 8 r - 28 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 28) = 411

r_{1, 2} = \frac{- ( - 8 ) \pm 4 11}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 8 ) + 4 11}{2 \cdot 1}, r_{2} = \frac{- ( - 8 ) - 4 11}{2 \cdot 1}

r = \frac{- ( - 8 ) + 4 11}{2 \cdot 1} : 2 (2 + 11)

r = \frac{- ( - 8 ) - 4 11}{2 \cdot 1} : 2 (2 - 11)

The solutions to the quadratic equation are:

r = 2 (2 + 11), r = 2 (2 - 11)

a x^{2} = 0

3 x^{2} + 5 = x^{2} - 2

t, x = \frac{1}{2} g t^{2}

6^{2} + 4^{2} = x^{2}

- 5 x^{2} + 100 x - 680 = 0

What are the solutions to the equation r^2-8r-22=6 ?
The solutions to the equation r^2-8r-22=6 are r=2(2+sqrt(11)),r=2(2-sqrt(11))
Find the zeros of r^2-8r-22=6
The zeros of r^2-8r-22=6 are r=2(2+sqrt(11)),r=2(2-sqrt(11))