What are the solutions to the equation 6^2+4^2=x^2 ?

The solutions to the equation 6^2+4^2=x^2 are x=2sqrt(13),x=-2sqrt(13)

Find the zeros of 6^2+4^2=x^2

The zeros of 6^2+4^2=x^2 are x=2sqrt(13),x=-2sqrt(13)

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6^{2} + 4^{2} = x^{2}

x = 213, x = - 213

Decimal Notation

x = 7.21110 \dots, x = - 7.21110 \dots

Solution steps

6^{2} + 4^{2} = x^{2}

Switch sides

x^{2} = 6^{2} + 4^{2}

Simplify

6^{2} + 4^{2} : 52

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 52, x = - 52

52 = 213

- 52 = - 213

x = 213, x = - 213

- 5 x^{2} + 100 x - 680 = 0

x (x + 2) + (x + 3)^{2} = 0

3 x^{2} + 12 x + 11 = 0

3 x^{2} + 13 = - 12 x

x, x^{2} - x y + y^{2} = 9

What are the solutions to the equation 6^2+4^2=x^2 ?
The solutions to the equation 6^2+4^2=x^2 are x=2sqrt(13),x=-2sqrt(13)
Find the zeros of 6^2+4^2=x^2
The zeros of 6^2+4^2=x^2 are x=2sqrt(13),x=-2sqrt(13)