What are the solutions to the equation -4x^2-80x-700=0 ?

The solutions to the equation -4x^2-80x-700=0 are x=-10-5sqrt(3)i,x=-10+5sqrt(3)i

Find the zeros of -4x^2-80x-700=0

The zeros of -4x^2-80x-700=0 are x=-10-5sqrt(3)i,x=-10+5sqrt(3)i

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- 4 x^{2} - 80 x - 700 = 0

x = - 10 - 53 i, x = - 10 + 53 i

Solution steps

- 4 x^{2} - 80 x - 700 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 80 ) \pm ( - 80 ) ^{2} - 4 ( - 4 ) ( - 700 )}{2 ( - 4 )}

Simplify

(- 80)^{2} - 4 (- 4) (- 700) : 403 i

x_{1, 2} = \frac{- ( - 80 ) \pm 40 3 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 80 ) + 40 3 i}{2 ( - 4 )}, x_{2} = \frac{- ( - 80 ) - 40 3 i}{2 ( - 4 )}

x = \frac{- ( - 80 ) + 40 3 i}{2 ( - 4 )} : - 10 - 53 i

x = \frac{- ( - 80 ) - 40 3 i}{2 ( - 4 )} : - 10 + 53 i

The solutions to the quadratic equation are:

x = - 10 - 53 i, x = - 10 + 53 i

x (x + 1) = 20

2 (x - 3)^{2} + 1 = 73

x^{2} - 35 = 0

9 x^{2} - x = 0

y^{2} = - 1

What are the solutions to the equation -4x^2-80x-700=0 ?
The solutions to the equation -4x^2-80x-700=0 are x=-10-5sqrt(3)i,x=-10+5sqrt(3)i
Find the zeros of -4x^2-80x-700=0
The zeros of -4x^2-80x-700=0 are x=-10-5sqrt(3)i,x=-10+5sqrt(3)i