What are the solutions to the equation 2(x-3)^2+1=73 ?

The solutions to the equation 2(x-3)^2+1=73 are x=9,x=-3

Find the zeros of 2(x-3)^2+1=73

The zeros of 2(x-3)^2+1=73 are x=9,x=-3

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2 (x - 3)^{2} + 1 = 73

x = 9, x = - 3

Solution steps

2 (x - 3)^{2} + 1 = 73

Move

1

to the right side

2 (x - 3)^{2} = 72

Divide both sides by

2

(x - 3)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 36 : x = 9

Solve

x - 3 = - 36 : x = - 3

The solutions to the quadratic equation are:

x = 9, x = - 3

x^{2} - 35 = 0

9 x^{2} - x = 0

y^{2} = - 1

(2 x + 1) (2 x + 3) - 4 x = (4 x + 2) (2 - x)

5 (2 x + 1)^{2} + 6 = 26

What are the solutions to the equation 2(x-3)^2+1=73 ?
The solutions to the equation 2(x-3)^2+1=73 are x=9,x=-3
Find the zeros of 2(x-3)^2+1=73
The zeros of 2(x-3)^2+1=73 are x=9,x=-3