What are the solutions to the equation 5(2x+1)^2+6=26 ?

The solutions to the equation 5(2x+1)^2+6=26 are x= 1/2 ,x=-3/2

Find the zeros of 5(2x+1)^2+6=26

The zeros of 5(2x+1)^2+6=26 are x= 1/2 ,x=-3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 (2 x + 1)^{2} + 6 = 26

x = \frac{1}{2}, x = - \frac{3}{2}

Decimal Notation

x = 0.5, x = - 1.5

Solution steps

5 (2 x + 1)^{2} + 6 = 26

Move

6

to the right side

5 (2 x + 1)^{2} = 20

Divide both sides by

5

(2 x + 1)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 1 = 4 : x = \frac{1}{2}

Solve

2 x + 1 = - 4 : x = - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{3}{2}

(n + 1) (x^{2} + 2 x) = (n + 3) (3 x + 5)

- 3 w^{2} - 10 w + 1 = - 4 w^{2}

x^{2} - 19 x + 84 = 0

x^{2} + \frac{2}{3} x + 5

2 x^{2} - 5 = - 3 x

What are the solutions to the equation 5(2x+1)^2+6=26 ?
The solutions to the equation 5(2x+1)^2+6=26 are x= 1/2 ,x=-3/2
Find the zeros of 5(2x+1)^2+6=26
The zeros of 5(2x+1)^2+6=26 are x= 1/2 ,x=-3/2