What are the solutions to the equation x^2-19x+84=0 ?

The solutions to the equation x^2-19x+84=0 are x=12,x=7

Find the zeros of x^2-19x+84=0

The zeros of x^2-19x+84=0 are x=12,x=7

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x^{2} - 19 x + 84 = 0

x = 12, x = 7

Solution steps

x^{2} - 19 x + 84 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 1 \cdot 84}{2 \cdot 1}

(- 19)^{2} - 4 \cdot 1 \cdot 84 = 5

x_{1, 2} = \frac{- ( - 19 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 19 ) - 5}{2 \cdot 1}

x = \frac{- ( - 19 ) + 5}{2 \cdot 1} : 12

x = \frac{- ( - 19 ) - 5}{2 \cdot 1} : 7

The solutions to the quadratic equation are:

x = 12, x = 7

x^{2} + \frac{2}{3} x + 5

2 x^{2} - 5 = - 3 x

5 x^{2} - 10 x + 3

(7 x + 8) (2 x - 11) = 0

x^{2} - 5 = - 4

What are the solutions to the equation x^2-19x+84=0 ?
The solutions to the equation x^2-19x+84=0 are x=12,x=7
Find the zeros of x^2-19x+84=0
The zeros of x^2-19x+84=0 are x=12,x=7