What are the solutions to the equation (x-6)(x-10)=60 ?

The solutions to the equation (x-6)(x-10)=60 are x=16,x=0

Find the zeros of (x-6)(x-10)=60

The zeros of (x-6)(x-10)=60 are x=16,x=0

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(x - 6) (x - 10) = 60

x = 16, x = 0

Solution steps

(x - 6) (x - 10) = 60

Expand

(x - 6) (x - 10) : x^{2} - 16 x + 60

x^{2} - 16 x + 60 = 60

Move

60

to the left side

x^{2} - 16 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 0 = 16

x_{1, 2} = \frac{- ( - 16 ) \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 16}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 16}{2 \cdot 1}

x = \frac{- ( - 16 ) + 16}{2 \cdot 1} : 16

x = \frac{- ( - 16 ) - 16}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 16, x = 0

2 x^{2} - 6 x - 56 = 0

5 (2 x - 10)^{2} - 14 = 21

3 x^{2} + 6 x - 1 = 2 x^{2} + 13 x - 7

5 x^{2} - 6 = 13 x

25 q^{2} + 15 q + 1 = 5 q

What are the solutions to the equation (x-6)(x-10)=60 ?
The solutions to the equation (x-6)(x-10)=60 are x=16,x=0
Find the zeros of (x-6)(x-10)=60
The zeros of (x-6)(x-10)=60 are x=16,x=0