What are the solutions to the equation 5(2x-10)^2-14=21 ?

The solutions to the equation 5(2x-10)^2-14=21 are x=(sqrt(7)+10)/2 ,x=(-sqrt(7)+10)/2

Find the zeros of 5(2x-10)^2-14=21

The zeros of 5(2x-10)^2-14=21 are x=(sqrt(7)+10)/2 ,x=(-sqrt(7)+10)/2

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5 (2 x - 10)^{2} - 14 = 21

x = \frac{7 + 10}{2}, x = \frac{- 7 + 10}{2}

Decimal Notation

x = 6.32287 \dots, x = 3.67712 \dots

Solution steps

5 (2 x - 10)^{2} - 14 = 21

Move

14

to the right side

5 (2 x - 10)^{2} = 35

Divide both sides by

5

(2 x - 10)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 10 = 7 : x = \frac{7 + 10}{2}

Solve

2 x - 10 = - 7 : x = \frac{- 7 + 10}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 10}{2}, x = \frac{- 7 + 10}{2}

3 x^{2} + 6 x - 1 = 2 x^{2} + 13 x - 7

5 x^{2} - 6 = 13 x

25 q^{2} + 15 q + 1 = 5 q

3 x^{2} + 7 x - 9 = 0

3 x^{2} - 12 = - x

What are the solutions to the equation 5(2x-10)^2-14=21 ?
The solutions to the equation 5(2x-10)^2-14=21 are x=(sqrt(7)+10)/2 ,x=(-sqrt(7)+10)/2
Find the zeros of 5(2x-10)^2-14=21
The zeros of 5(2x-10)^2-14=21 are x=(sqrt(7)+10)/2 ,x=(-sqrt(7)+10)/2