What are the solutions to the equation x^2+4b=0 ?

The solutions to the equation x^2+4b=0 are x=2sqrt(-b),x=-2sqrt(-b)

Find the zeros of x^2+4b=0

The zeros of x^2+4b=0 are x=2sqrt(-b),x=-2sqrt(-b)

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x^{2} + 4 b = 0

x = 2 - b, x = - 2 - b

Solution steps

x^{2} + 4 b = 0

Move

4 b

to the right side

x^{2} = - 4 b

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4 b, x = - - 4 b

Simplify

- 4 b : 2 - b

Simplify

- - 4 b : - 2 - b

x = 2 - b, x = - 2 - b

v^{2} - 4 v - 3 = 2 v

x^{2} + 225 = 0

x^{2} - 4 x + 4 = 0

x^{2} - 22 x = 75

x^{2} + 6 = - 10 x

What are the solutions to the equation x^2+4b=0 ?
The solutions to the equation x^2+4b=0 are x=2sqrt(-b),x=-2sqrt(-b)
Find the zeros of x^2+4b=0
The zeros of x^2+4b=0 are x=2sqrt(-b),x=-2sqrt(-b)