What are the solutions to the equation b^2=16 ?

The solutions to the equation b^2=16 are b=4,b=-4

Find the zeros of b^2=16

The zeros of b^2=16 are b=4,b=-4

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b^{2} = 16

b = 4, b = - 4

Solution steps

b^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 16, b = - 16

16 = 4

- 16 = - 4

b = 4, b = - 4

x^{2} - 28 x + 147 = 0

x^{2} + 10 + 25 = 0

(2 x - 5) (2 x + 5) - 119 = 0

x^{2} - 10 x + 28 = 0

y, y^{2} = x^{2}

What are the solutions to the equation b^2=16 ?
The solutions to the equation b^2=16 are b=4,b=-4
Find the zeros of b^2=16
The zeros of b^2=16 are b=4,b=-4