What are the solutions to the equation (3x+2)^2=121 ?

The solutions to the equation (3x+2)^2=121 are x=3,x=-13/3

Find the zeros of (3x+2)^2=121

The zeros of (3x+2)^2=121 are x=3,x=-13/3

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(3 x + 2)^{2} = 121

x = 3, x = - \frac{13}{3}

Decimal Notation

x = 3, x = - 4.33333 \dots

Solution steps

(3 x + 2)^{2} = 121

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 2 = 121 : x = 3

Solve

3 x + 2 = - 121 : x = - \frac{13}{3}

The solutions to the quadratic equation are:

x = 3, x = - \frac{13}{3}

9 (2 x - 1)^{2} - 8 = 0

2 (x^{2} + 4) = 10

\frac{x ^{2} - 8 x - 2}{3} = \frac{x ^{2} - 3 x + 2}{2}

x^{2} + 4 x + 13

(x - 5) (x - 8) = 0

What are the solutions to the equation (3x+2)^2=121 ?
The solutions to the equation (3x+2)^2=121 are x=3,x=-13/3
Find the zeros of (3x+2)^2=121
The zeros of (3x+2)^2=121 are x=3,x=-13/3