What are the solutions to the equation -x^2+12x-27=0 ?

The solutions to the equation -x^2+12x-27=0 are x=3,x=9

Find the zeros of -x^2+12x-27=0

The zeros of -x^2+12x-27=0 are x=3,x=9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} + 12 x - 27 = 0

x = 3, x = 9

Solution steps

- x^{2} + 12 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 1 ) ( - 27 )}{2 ( - 1 )}

1 2^{2} - 4 (- 1) (- 27) = 6

x_{1, 2} = \frac{- 12 \pm 6}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 12 + 6}{2 ( - 1 )}, x_{2} = \frac{- 12 - 6}{2 ( - 1 )}

x = \frac{- 12 + 6}{2 ( - 1 )} : 3

x = \frac{- 12 - 6}{2 ( - 1 )} : 9

The solutions to the quadratic equation are:

x = 3, x = 9

0 = z^{2} - 10 z + 25

4 m^{2} + 2 m - 19 = 3 m^{2}

- 3 x^{2} + 2 x + 5 = 0

2 x^{2} + 8 x + 5

2 x^{2} + 8 x + 3

What are the solutions to the equation -x^2+12x-27=0 ?
The solutions to the equation -x^2+12x-27=0 are x=3,x=9
Find the zeros of -x^2+12x-27=0
The zeros of -x^2+12x-27=0 are x=3,x=9