What are the solutions to the equation -21x^2+7x=0 ?

The solutions to the equation -21x^2+7x=0 are x=0,x= 1/3

Find the zeros of -21x^2+7x=0

The zeros of -21x^2+7x=0 are x=0,x= 1/3

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- 21 x^{2} + 7 x = 0

x = 0, x = \frac{1}{3}

Decimal Notation

x = 0, x = 0.33333 \dots

Solution steps

- 21 x^{2} + 7 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 21 ) \cdot 0}{2 ( - 21 )}

7^{2} - 4 (- 21) \cdot 0 = 7

x_{1, 2} = \frac{- 7 \pm 7}{2 ( - 21 )}

Separate the solutions

x_{1} = \frac{- 7 + 7}{2 ( - 21 )}, x_{2} = \frac{- 7 - 7}{2 ( - 21 )}

x = \frac{- 7 + 7}{2 ( - 21 )} : 0

x = \frac{- 7 - 7}{2 ( - 21 )} : \frac{1}{3}

The solutions to the quadratic equation are:

x = 0, x = \frac{1}{3}

6 n^{2} - 6 n + 3 = 4 n^{2}

- 2 x^{2} + x - 3 = 0

x^{2} = (x - 8)^{2} + (x - 1)^{2}

- 2 x^{2} + x - 1 = 0

4 (x + 2) (x + 3) - 6 x = 12

What are the solutions to the equation -21x^2+7x=0 ?
The solutions to the equation -21x^2+7x=0 are x=0,x= 1/3
Find the zeros of -21x^2+7x=0
The zeros of -21x^2+7x=0 are x=0,x= 1/3