What are the solutions to the equation 4*8^2=d^2+d^2 ?

The solutions to the equation 4*8^2=d^2+d^2 are d=8sqrt(2),d=-8sqrt(2)

Find the zeros of 4*8^2=d^2+d^2

The zeros of 4*8^2=d^2+d^2 are d=8sqrt(2),d=-8sqrt(2)

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4 \cdot 8^{2} = d^{2} + d^{2}

d = 82, d = - 82

Decimal Notation

d = 11.31370 \dots, d = - 11.31370 \dots

Solution steps

4 \cdot 8^{2} = d^{2} + d^{2}

Switch sides

d^{2} + d^{2} = 4 \cdot 8^{2}

Add similar elements:

d^{2} + d^{2} = 2 d^{2}

2 d^{2} = 4 \cdot 8^{2}

8^{2} = 64

2 d^{2} = 4 \cdot 64

Multiply the numbers:

4 \cdot 64 = 256

2 d^{2} = 256

Divide both sides by

2

d^{2} = 128

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

d = 128, d = - 128

128 = 82

- 128 = - 82

d = 82, d = - 82

x, \frac{x ^{2} + y ^{3}}{y} - 4 x^{2} y = 4

x^{2} - 5 x + 1 = 0

x^{2} - 8 x + 15

2 x^{2} + 2 x - 9 = 0

y^{2} - 8 y + 15 = 0

What are the solutions to the equation 4*8^2=d^2+d^2 ?
The solutions to the equation 4*8^2=d^2+d^2 are d=8sqrt(2),d=-8sqrt(2)
Find the zeros of 4*8^2=d^2+d^2
The zeros of 4*8^2=d^2+d^2 are d=8sqrt(2),d=-8sqrt(2)