What are the solutions to the equation x^2-sqrt(5)x+1=0 ?

The solutions to the equation x^2-sqrt(5)x+1=0 are x=(sqrt(5)+1)/2 ,x=(sqrt(5)-1)/2

Find the zeros of x^2-sqrt(5)x+1=0

The zeros of x^2-sqrt(5)x+1=0 are x=(sqrt(5)+1)/2 ,x=(sqrt(5)-1)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 5 x + 1 = 0

x = \frac{5 + 1}{2}, x = \frac{5 - 1}{2}

Decimal Notation

x = 1.61803 \dots, x = 0.61803 \dots

Solution steps

x^{2} - 5 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 1 = 1

x_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 1}

x = \frac{- ( - 5 ) + 1}{2 \cdot 1} : \frac{5 + 1}{2}

x = \frac{- ( - 5 ) - 1}{2 \cdot 1} : \frac{5 - 1}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 1}{2}, x = \frac{5 - 1}{2}

x^{2} - 8 x + 15

2 x^{2} + 2 x - 9 = 0

y^{2} - 8 y + 15 = 0

(4 x + 2)^{2} = 10

x^{2} + 10 x = 11

What are the solutions to the equation x^2-sqrt(5)x+1=0 ?
The solutions to the equation x^2-sqrt(5)x+1=0 are x=(sqrt(5)+1)/2 ,x=(sqrt(5)-1)/2
Find the zeros of x^2-sqrt(5)x+1=0
The zeros of x^2-sqrt(5)x+1=0 are x=(sqrt(5)+1)/2 ,x=(sqrt(5)-1)/2