What are the solutions to the equation (4x+2)^2=10 ?

The solutions to the equation (4x+2)^2=10 are x=(sqrt(10)-2)/4 ,x=(-sqrt(10)-2)/4

Find the zeros of (4x+2)^2=10

The zeros of (4x+2)^2=10 are x=(sqrt(10)-2)/4 ,x=(-sqrt(10)-2)/4

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(4 x + 2)^{2} = 10

x = \frac{10 - 2}{4}, x = \frac{- 10 - 2}{4}

Decimal Notation

x = 0.29056 \dots, x = - 1.29056 \dots

Solution steps

(4 x + 2)^{2} = 10

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 2 = 10 : x = \frac{10 - 2}{4}

Solve

4 x + 2 = - 10 : x = \frac{- 10 - 2}{4}

The solutions to the quadratic equation are:

x = \frac{10 - 2}{4}, x = \frac{- 10 - 2}{4}

x^{2} + 10 x = 11

7 - \frac{x ^{2}}{4} - \frac{4 x}{3} = 0

12 x^{2} - 156 x + 350 = 0

x^{2} + 5 x = 2.75

x^{2} - x = 0

What are the solutions to the equation (4x+2)^2=10 ?
The solutions to the equation (4x+2)^2=10 are x=(sqrt(10)-2)/4 ,x=(-sqrt(10)-2)/4
Find the zeros of (4x+2)^2=10
The zeros of (4x+2)^2=10 are x=(sqrt(10)-2)/4 ,x=(-sqrt(10)-2)/4