What are the solutions to the equation -6p^2+18000p=0 ?

The solutions to the equation -6p^2+18000p=0 are p=0,p=3000

Find the zeros of -6p^2+18000p=0

The zeros of -6p^2+18000p=0 are p=0,p=3000

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- 6 p^{2} + 18000 p = 0

p = 0, p = 3000

Solution steps

- 6 p^{2} + 18000 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 18000 \pm 1800 0 ^{2} - 4 ( - 6 ) \cdot 0}{2 ( - 6 )}

1800 0^{2} - 4 (- 6) \cdot 0 = 18000

p_{1, 2} = \frac{- 18000 \pm 18000}{2 ( - 6 )}

Separate the solutions

p_{1} = \frac{- 18000 + 18000}{2 ( - 6 )}, p_{2} = \frac{- 18000 - 18000}{2 ( - 6 )}

p = \frac{- 18000 + 18000}{2 ( - 6 )} : 0

p = \frac{- 18000 - 18000}{2 ( - 6 )} : 3000

The solutions to the quadratic equation are:

p = 0, p = 3000

- 2 \leq \frac{4 x - 1}{3} \leq 5

x^{2} + 6 x = 216

x^{2} + x - 1 \leq 5

- 1 + \frac{4}{3}

- \frac{1}{5} \cdot 1

What are the solutions to the equation -6p^2+18000p=0 ?
The solutions to the equation -6p^2+18000p=0 are p=0,p=3000
Find the zeros of -6p^2+18000p=0
The zeros of -6p^2+18000p=0 are p=0,p=3000