What are the solutions to the equation x^2+6x+C=40 ?

The solutions to the equation x^2+6x+C=40 are x=-3+sqrt(-C+49),x=-sqrt(-C+49)-3

Find the zeros of x^2+6x+C=40

The zeros of x^2+6x+C=40 are x=-3+sqrt(-C+49),x=-sqrt(-C+49)-3

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x^{2} + 6 x + C = 40

x = - 3 + - C + 49, x = - - C + 49 - 3

Solution steps

x^{2} + 6 x + C = 40

Move

40

to the left side

x^{2} + 6 x + C - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( C - 40 )}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot (C - 40) : 2 - C + 49

x_{1, 2} = \frac{- 6 \pm 2 - C + 49}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 - C + 49}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 - C + 49}{2 \cdot 1}

x = \frac{- 6 + 2 - C + 49}{2 \cdot 1} : - 3 + - C + 49

x = \frac{- 6 - 2 - C + 49}{2 \cdot 1} : - - C + 49 - 3

The solutions to the quadratic equation are:

x = - 3 + - C + 49, x = - - C + 49 - 3

4 - 3 x^{2} = 0

(6 x + 6)^{2} = 1

2 x^{2} + 9 x + 3 = 0

b^{2} - 2 b - 15 = 0

2 x (x + 3) = 0

What are the solutions to the equation x^2+6x+C=40 ?
The solutions to the equation x^2+6x+C=40 are x=-3+sqrt(-C+49),x=-sqrt(-C+49)-3
Find the zeros of x^2+6x+C=40
The zeros of x^2+6x+C=40 are x=-3+sqrt(-C+49),x=-sqrt(-C+49)-3