What are the solutions to the equation 2x^2+9x+3=0 ?

The solutions to the equation 2x^2+9x+3=0 are x=(-9+sqrt(57))/4 ,x=(-9-sqrt(57))/4

Find the zeros of 2x^2+9x+3=0

The zeros of 2x^2+9x+3=0 are x=(-9+sqrt(57))/4 ,x=(-9-sqrt(57))/4

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2 x^{2} + 9 x + 3 = 0

x = \frac{- 9 + 57}{4}, x = \frac{- 9 - 57}{4}

Decimal Notation

x = - 0.36254 \dots, x = - 4.13745 \dots

Solution steps

2 x^{2} + 9 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

9^{2} - 4 \cdot 2 \cdot 3 = 57

x_{1, 2} = \frac{- 9 \pm 57}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 9 + 57}{2 \cdot 2}, x_{2} = \frac{- 9 - 57}{2 \cdot 2}

x = \frac{- 9 + 57}{2 \cdot 2} : \frac{- 9 + 57}{4}

x = \frac{- 9 - 57}{2 \cdot 2} : \frac{- 9 - 57}{4}

The solutions to the quadratic equation are:

x = \frac{- 9 + 57}{4}, x = \frac{- 9 - 57}{4}

b^{2} - 2 b - 15 = 0

2 x (x + 3) = 0

4 n^{2} = 81

6 x^{2} - 4 x + 5 = 0

t, s = \frac{1}{2} g t^{2}

What are the solutions to the equation 2x^2+9x+3=0 ?
The solutions to the equation 2x^2+9x+3=0 are x=(-9+sqrt(57))/4 ,x=(-9-sqrt(57))/4
Find the zeros of 2x^2+9x+3=0
The zeros of 2x^2+9x+3=0 are x=(-9+sqrt(57))/4 ,x=(-9-sqrt(57))/4