What are the solutions to the equation 25-70x+49x^2=0 ?

The solutions to the equation 25-70x+49x^2=0 are x= 5/7

Find the zeros of 25-70x+49x^2=0

The zeros of 25-70x+49x^2=0 are x= 5/7

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25 - 70 x + 49 x^{2} = 0

x = \frac{5}{7}

Decimal Notation

x = 0.71428 \dots

Solution steps

25 - 70 x + 49 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

49 x^{2} - 70 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 70 ) \pm ( - 70 ) ^{2} - 4 \cdot 49 \cdot 25}{2 \cdot 49}

(- 70)^{2} - 4 \cdot 49 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 70 ) \pm 0}{2 \cdot 49}

x = \frac{- ( - 70 )}{2 \cdot 49}

\frac{- ( - 70 )}{2 \cdot 49} = \frac{5}{7}

x = \frac{5}{7}

The solution to the quadratic equation is:

x = \frac{5}{7}

2 x^{2} - 12 x + 11

12 x = 13 - x^{2}

- 2 x^{2} + 7 x + 1 = 17

t^{2} - t + 1 = 0

x^{2} + 3 x - 2

What are the solutions to the equation 25-70x+49x^2=0 ?
The solutions to the equation 25-70x+49x^2=0 are x= 5/7
Find the zeros of 25-70x+49x^2=0
The zeros of 25-70x+49x^2=0 are x= 5/7