What are the solutions to the equation 10-(x-3)^2=5 ?

The solutions to the equation 10-(x-3)^2=5 are x=sqrt(5)+3,x=-sqrt(5)+3

Find the zeros of 10-(x-3)^2=5

The zeros of 10-(x-3)^2=5 are x=sqrt(5)+3,x=-sqrt(5)+3

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10 - (x - 3)^{2} = 5

x = 5 + 3, x = - 5 + 3

Decimal Notation

x = 5.23606 \dots, x = 0.76393 \dots

Solution steps

10 - (x - 3)^{2} = 5

Move

10

to the right side

- (x - 3)^{2} = - 5

Divide both sides by

- 1

(x - 3)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 5 : x = 5 + 3

Solve

x - 3 = - 5 : x = - 5 + 3

The solutions to the quadratic equation are:

x = 5 + 3, x = - 5 + 3

4 x^{2} = 20 x - 25

8 x^{2} - 6 x - 9 = 0

4 x^{2} - 23 x + 15 = 0

4 x^{2} + 2 x = 12

y, z = x^{2} + y^{2}

What are the solutions to the equation 10-(x-3)^2=5 ?
The solutions to the equation 10-(x-3)^2=5 are x=sqrt(5)+3,x=-sqrt(5)+3
Find the zeros of 10-(x-3)^2=5
The zeros of 10-(x-3)^2=5 are x=sqrt(5)+3,x=-sqrt(5)+3