What are the solutions to the equation 4x^2+2x=12 ?

The solutions to the equation 4x^2+2x=12 are x= 3/2 ,x=-2

Find the zeros of 4x^2+2x=12

The zeros of 4x^2+2x=12 are x= 3/2 ,x=-2

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4 x^{2} + 2 x = 12

x = \frac{3}{2}, x = - 2

Decimal Notation

x = 1.5, x = - 2

Solution steps

4 x^{2} + 2 x = 12

Move

12

to the left side

4 x^{2} + 2 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 4 ( - 12 )}{2 \cdot 4}

2^{2} - 4 \cdot 4 (- 12) = 14

x_{1, 2} = \frac{- 2 \pm 14}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 2 + 14}{2 \cdot 4}, x_{2} = \frac{- 2 - 14}{2 \cdot 4}

x = \frac{- 2 + 14}{2 \cdot 4} : \frac{3}{2}

x = \frac{- 2 - 14}{2 \cdot 4} : - 2

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 2

y, z = x^{2} + y^{2}

x^{2} - 8 x + a = 0

x^{2} - 4 x + 3 = 0

3 y^{2} - 6 y - 9 = 0

4 x^{2} + 3 = - 11 x + 6

What are the solutions to the equation 4x^2+2x=12 ?
The solutions to the equation 4x^2+2x=12 are x= 3/2 ,x=-2
Find the zeros of 4x^2+2x=12
The zeros of 4x^2+2x=12 are x= 3/2 ,x=-2