What are the solutions to the equation λ^2-4λ-5=0 ?

The solutions to the equation λ^2-4λ-5=0 are λ=5,λ=-1

Find the zeros of λ^2-4λ-5=0

The zeros of λ^2-4λ-5=0 are λ=5,λ=-1

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λ^{2} - 4 λ - 5 = 0

λ = 5, λ = - 1

Solution steps

λ^{2} - 4 λ - 5 = 0

Solve with the quadratic formula

λ_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 5) = 6

λ_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 1}

Separate the solutions

λ_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 1}, λ_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 1}

λ = \frac{- ( - 4 ) + 6}{2 \cdot 1} : 5

λ = \frac{- ( - 4 ) - 6}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

λ = 5, λ = - 1

x^{2} - 22 x + 112 = 0

x^{2} + 6 x = - 18

3 x^{2} + 9 x + 5 = 0

9^{2} + 4^{2} = x^{2}

2 x^{2} + 8 x - 42 = 0

What are the solutions to the equation λ^2-4λ-5=0 ?
The solutions to the equation λ^2-4λ-5=0 are λ=5,λ=-1
Find the zeros of λ^2-4λ-5=0
The zeros of λ^2-4λ-5=0 are λ=5,λ=-1