What are the solutions to the equation (4x-7)(x+3)=0 ?

The solutions to the equation (4x-7)(x+3)=0 are x= 7/4 ,x=-3

Find the zeros of (4x-7)(x+3)=0

The zeros of (4x-7)(x+3)=0 are x= 7/4 ,x=-3

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(4 x - 7) (x + 3) = 0

x = \frac{7}{4}, x = - 3

Decimal Notation

x = 1.75, x = - 3

Solution steps

(4 x - 7) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x - 7 = 0 or x + 3 = 0

Solve

4 x - 7 = 0 : x = \frac{7}{4}

Solve

x + 3 = 0 : x = - 3

The solutions to the quadratic equation are:

x = \frac{7}{4}, x = - 3

3 x^{2} + 36 x + 300 = 0

4 x^{2} + 12 x = 7

0 = x^{2} + 8 x + 12

X^{2} + 11 X + 24 = 0

x, x y^{2} - x^{2} + 4 = 0

What are the solutions to the equation (4x-7)(x+3)=0 ?
The solutions to the equation (4x-7)(x+3)=0 are x= 7/4 ,x=-3
Find the zeros of (4x-7)(x+3)=0
The zeros of (4x-7)(x+3)=0 are x= 7/4 ,x=-3