What are the solutions to the equation X^2+11X+24=0 ?

The solutions to the equation X^2+11X+24=0 are X=-3,X=-8

Find the zeros of X^2+11X+24=0

The zeros of X^2+11X+24=0 are X=-3,X=-8

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X^{2} + 11 X + 24 = 0

X = - 3, X = - 8

Solution steps

X^{2} + 11 X + 24 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 24 = 5

X_{1, 2} = \frac{- 11 \pm 5}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- 11 + 5}{2 \cdot 1}, X_{2} = \frac{- 11 - 5}{2 \cdot 1}

X = \frac{- 11 + 5}{2 \cdot 1} : - 3

X = \frac{- 11 - 5}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

X = - 3, X = - 8

x, x y^{2} - x^{2} + 4 = 0

3 x^{2} - 7 x - \frac{8}{7} = 0

- x^{2} + 3 x - 8 = 0

2 x^{2} + 4 x + 1 = 0

25 z^{2} - 36 = 0

What are the solutions to the equation X^2+11X+24=0 ?
The solutions to the equation X^2+11X+24=0 are X=-3,X=-8
Find the zeros of X^2+11X+24=0
The zeros of X^2+11X+24=0 are X=-3,X=-8