What are the solutions to the equation solvefor a,a^2+b^2+c^2=0 ?

The solutions to the equation solvefor a,a^2+b^2+c^2=0 are a=sqrt(-b^2-c^2),a=-sqrt(-b^2-c^2)

Find the zeros of solvefor a,a^2+b^2+c^2=0

The zeros of solvefor a,a^2+b^2+c^2=0 are a=sqrt(-b^2-c^2),a=-sqrt(-b^2-c^2)

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solve for

a, a^{2} + b^{2} + c^{2} = 0

a = - b^{2} - c^{2}, a = - - b^{2} - c^{2}

Solution steps

a^{2} + b^{2} + c^{2} = 0

Move

b^{2}

to the right side

a^{2} + c^{2} = - b^{2}

Move

c^{2}

to the right side

a^{2} = - b^{2} - c^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = - b^{2} - c^{2}, a = - - b^{2} - c^{2}

(x - 7) (x - 7) = 0

y, 2 x^{3} = (3 x y + 1)^{2}

x^{2} - 8 x = 4 x - 38

y^{2} - 16 y + 64 = 0

(2 x + 4)^{2} - 4 = 0

What are the solutions to the equation solvefor a,a^2+b^2+c^2=0 ?
The solutions to the equation solvefor a,a^2+b^2+c^2=0 are a=sqrt(-b^2-c^2),a=-sqrt(-b^2-c^2)
Find the zeros of solvefor a,a^2+b^2+c^2=0
The zeros of solvefor a,a^2+b^2+c^2=0 are a=sqrt(-b^2-c^2),a=-sqrt(-b^2-c^2)