What are the solutions to the equation y^2-16y+64=0 ?

The solutions to the equation y^2-16y+64=0 are y=8

Find the zeros of y^2-16y+64=0

The zeros of y^2-16y+64=0 are y=8

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y^{2} - 16 y + 64 = 0

y = 8

Solution steps

y^{2} - 16 y + 64 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 64 = 0

y_{1, 2} = \frac{- ( - 16 ) \pm 0}{2 \cdot 1}

y = \frac{- ( - 16 )}{2 \cdot 1}

\frac{- ( - 16 )}{2 \cdot 1} = 8

y = 8

The solution to the quadratic equation is:

y = 8

(2 x + 4)^{2} - 4 = 0

x^{2} + 2 x + 1 = 0

4 (6 - 3 x)^{2} - 38 = - 37

m^{2} + 10 m + 25 = 0

x (2 x + 1) = 0

What are the solutions to the equation y^2-16y+64=0 ?
The solutions to the equation y^2-16y+64=0 are y=8
Find the zeros of y^2-16y+64=0
The zeros of y^2-16y+64=0 are y=8