What are the solutions to the equation m^2+10m+25=0 ?

The solutions to the equation m^2+10m+25=0 are m=-5

Find the zeros of m^2+10m+25=0

The zeros of m^2+10m+25=0 are m=-5

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m^{2} + 10 m + 25 = 0

m = - 5

Solution steps

m^{2} + 10 m + 25 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 25 = 0

m_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 1}

m = \frac{- 10}{2 \cdot 1}

\frac{- 10}{2 \cdot 1} = - 5

m = - 5

The solution to the quadratic equation is:

m = - 5

x (2 x + 1) = 0

x, x^{2} + x - 2 = 0

7 v^{2} - 42 = - 35 v

x^{2} - 2 x + 3 = 0

x^{2} - \frac{4}{3} x + \frac{1}{3} = 0

What are the solutions to the equation m^2+10m+25=0 ?
The solutions to the equation m^2+10m+25=0 are m=-5
Find the zeros of m^2+10m+25=0
The zeros of m^2+10m+25=0 are m=-5