What are the solutions to the equation 12x^2-72x+77=0 ?

The solutions to the equation 12x^2-72x+77=0 are x=(18+sqrt(93))/6 ,x=(18-sqrt(93))/6

Find the zeros of 12x^2-72x+77=0

The zeros of 12x^2-72x+77=0 are x=(18+sqrt(93))/6 ,x=(18-sqrt(93))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12 x^{2} - 72 x + 77 = 0

x = \frac{18 + 93}{6}, x = \frac{18 - 93}{6}

Decimal Notation

x = 4.60727 \dots, x = 1.39272 \dots

Solution steps

12 x^{2} - 72 x + 77 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 72 ) \pm ( - 72 ) ^{2} - 4 \cdot 12 \cdot 77}{2 \cdot 12}

(- 72)^{2} - 4 \cdot 12 \cdot 77 = 493

x_{1, 2} = \frac{- ( - 72 ) \pm 4 93}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 72 ) + 4 93}{2 \cdot 12}, x_{2} = \frac{- ( - 72 ) - 4 93}{2 \cdot 12}

x = \frac{- ( - 72 ) + 4 93}{2 \cdot 12} : \frac{18 + 93}{6}

x = \frac{- ( - 72 ) - 4 93}{2 \cdot 12} : \frac{18 - 93}{6}

The solutions to the quadratic equation are:

x = \frac{18 + 93}{6}, x = \frac{18 - 93}{6}

x^{2} = \frac{4}{25}

x^{2} + 6 x + 20 = 0

0 = x^{2} - 3 x - 10

(x + 2)^{2} = 2

2 x^{2} - 16 x - 1 = 0

What are the solutions to the equation 12x^2-72x+77=0 ?
The solutions to the equation 12x^2-72x+77=0 are x=(18+sqrt(93))/6 ,x=(18-sqrt(93))/6
Find the zeros of 12x^2-72x+77=0
The zeros of 12x^2-72x+77=0 are x=(18+sqrt(93))/6 ,x=(18-sqrt(93))/6