What are the solutions to the equation 2x^2-16x-1=0 ?

The solutions to the equation 2x^2-16x-1=0 are x=(8+sqrt(66))/2 ,x=(8-sqrt(66))/2

Find the zeros of 2x^2-16x-1=0

The zeros of 2x^2-16x-1=0 are x=(8+sqrt(66))/2 ,x=(8-sqrt(66))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 16 x - 1 = 0

x = \frac{8 + 66}{2}, x = \frac{8 - 66}{2}

Decimal Notation

x = 8.06201 \dots, x = - 0.06201 \dots

Solution steps

2 x^{2} - 16 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

(- 16)^{2} - 4 \cdot 2 (- 1) = 266

x_{1, 2} = \frac{- ( - 16 ) \pm 2 66}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 66}{2 \cdot 2}, x_{2} = \frac{- ( - 16 ) - 2 66}{2 \cdot 2}

x = \frac{- ( - 16 ) + 2 66}{2 \cdot 2} : \frac{8 + 66}{2}

x = \frac{- ( - 16 ) - 2 66}{2 \cdot 2} : \frac{8 - 66}{2}

The solutions to the quadratic equation are:

x = \frac{8 + 66}{2}, x = \frac{8 - 66}{2}

7 x^{2} + 20 x + 23 = 0

6 x^{2} + 12 x - 90 = 0

x, (x^{2} + 4) y = 8

16 x^{2} - 8 x + 3 = 0

x^{2} + 12 x = - 22

What are the solutions to the equation 2x^2-16x-1=0 ?
The solutions to the equation 2x^2-16x-1=0 are x=(8+sqrt(66))/2 ,x=(8-sqrt(66))/2
Find the zeros of 2x^2-16x-1=0
The zeros of 2x^2-16x-1=0 are x=(8+sqrt(66))/2 ,x=(8-sqrt(66))/2