What are the solutions to the equation 6x^2+12x-90=0 ?

The solutions to the equation 6x^2+12x-90=0 are x=3,x=-5

Find the zeros of 6x^2+12x-90=0

The zeros of 6x^2+12x-90=0 are x=3,x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} + 12 x - 90 = 0

x = 3, x = - 5

Solution steps

6 x^{2} + 12 x - 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 6 ( - 90 )}{2 \cdot 6}

1 2^{2} - 4 \cdot 6 (- 90) = 48

x_{1, 2} = \frac{- 12 \pm 48}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 12 + 48}{2 \cdot 6}, x_{2} = \frac{- 12 - 48}{2 \cdot 6}

x = \frac{- 12 + 48}{2 \cdot 6} : 3

x = \frac{- 12 - 48}{2 \cdot 6} : - 5

The solutions to the quadratic equation are:

x = 3, x = - 5

x, (x^{2} + 4) y = 8

16 x^{2} - 8 x + 3 = 0

x^{2} + 12 x = - 22

- 7 - 8 x - x^{2}

2 x^{2} + 12 x = x^{2} + 8

What are the solutions to the equation 6x^2+12x-90=0 ?
The solutions to the equation 6x^2+12x-90=0 are x=3,x=-5
Find the zeros of 6x^2+12x-90=0
The zeros of 6x^2+12x-90=0 are x=3,x=-5