What are the solutions to the equation x^2+12x=-22 ?

The solutions to the equation x^2+12x=-22 are x=-6+sqrt(14),x=-6-sqrt(14)

Find the zeros of x^2+12x=-22

The zeros of x^2+12x=-22 are x=-6+sqrt(14),x=-6-sqrt(14)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 12 x = - 22

x = - 6 + 14, x = - 6 - 14

Decimal Notation

x = - 2.25834 \dots, x = - 9.74165 \dots

Solution steps

x^{2} + 12 x = - 22

Move

22

to the left side

x^{2} + 12 x + 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 22}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 22 = 214

x_{1, 2} = \frac{- 12 \pm 2 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 14}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 14}{2 \cdot 1}

x = \frac{- 12 + 2 14}{2 \cdot 1} : - 6 + 14

x = \frac{- 12 - 2 14}{2 \cdot 1} : - 6 - 14

The solutions to the quadratic equation are:

x = - 6 + 14, x = - 6 - 14

- 7 - 8 x - x^{2}

2 x^{2} + 12 x = x^{2} + 8

25 (3 - 5 x)^{2} - 4 = 12

y^{2} + 2 y - 2 = 0

x^{2} + x + 5

What are the solutions to the equation x^2+12x=-22 ?
The solutions to the equation x^2+12x=-22 are x=-6+sqrt(14),x=-6-sqrt(14)
Find the zeros of x^2+12x=-22
The zeros of x^2+12x=-22 are x=-6+sqrt(14),x=-6-sqrt(14)