What are the solutions to the equation 25(3-5x)^2-4=12 ?

The solutions to the equation 25(3-5x)^2-4=12 are x= 11/25 ,x= 19/25

Find the zeros of 25(3-5x)^2-4=12

The zeros of 25(3-5x)^2-4=12 are x= 11/25 ,x= 19/25

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

25 (3 - 5 x)^{2} - 4 = 12

x = \frac{11}{25}, x = \frac{19}{25}

Decimal Notation

x = 0.44, x = 0.76

Solution steps

25 (3 - 5 x)^{2} - 4 = 12

Move

4

to the right side

25 (3 - 5 x)^{2} = 16

Divide both sides by

25

(3 - 5 x)^{2} = \frac{16}{25}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 - 5 x = \frac{16}{25} : x = \frac{11}{25}

Solve

3 - 5 x = - \frac{16}{25} : x = \frac{19}{25}

The solutions to the quadratic equation are:

x = \frac{11}{25}, x = \frac{19}{25}

y^{2} + 2 y - 2 = 0

x^{2} + x + 5

9 (x^{2} - 14) - 12 = - 17

20 x^{2} = - 25 x

6 x^{2} - x = 1

What are the solutions to the equation 25(3-5x)^2-4=12 ?
The solutions to the equation 25(3-5x)^2-4=12 are x= 11/25 ,x= 19/25
Find the zeros of 25(3-5x)^2-4=12
The zeros of 25(3-5x)^2-4=12 are x= 11/25 ,x= 19/25