What are the solutions to the equation 20x^2=-25x ?

The solutions to the equation 20x^2=-25x are x=0,x=-5/4

Find the zeros of 20x^2=-25x

The zeros of 20x^2=-25x are x=0,x=-5/4

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20 x^{2} = - 25 x

x = 0, x = - \frac{5}{4}

Decimal Notation

x = 0, x = - 1.25

Solution steps

20 x^{2} = - 25 x

Move

25 x

to the left side

20 x^{2} + 25 x = 0

Factor

20 x^{2} + 25 x : 5 x (4 x + 5)

5 x (4 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 4 x + 5 = 0

Solve

4 x + 5 = 0 : x = - \frac{5}{4}

The solutions to the quadratic equation are:

x = 0, x = - \frac{5}{4}

6 x^{2} - x = 1

m^{2} = 14

3 x^{2} = 5 x - 6

x, x^{2} y + 3 x y^{3} - x = 3

4 y^{2} = 8 y - 3

What are the solutions to the equation 20x^2=-25x ?
The solutions to the equation 20x^2=-25x are x=0,x=-5/4
Find the zeros of 20x^2=-25x
The zeros of 20x^2=-25x are x=0,x=-5/4