What are the solutions to the equation -2x^2+12x-10=0 ?

The solutions to the equation -2x^2+12x-10=0 are x=1,x=5

Find the zeros of -2x^2+12x-10=0

The zeros of -2x^2+12x-10=0 are x=1,x=5

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- 2 x^{2} + 12 x - 10 = 0

x = 1, x = 5

Solution steps

- 2 x^{2} + 12 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 2 ) ( - 10 )}{2 ( - 2 )}

1 2^{2} - 4 (- 2) (- 10) = 8

x_{1, 2} = \frac{- 12 \pm 8}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 12 + 8}{2 ( - 2 )}, x_{2} = \frac{- 12 - 8}{2 ( - 2 )}

x = \frac{- 12 + 8}{2 ( - 2 )} : 1

x = \frac{- 12 - 8}{2 ( - 2 )} : 5

The solutions to the quadratic equation are:

x = 1, x = 5

x (3 x - 5) = 0

m^{2} + 10 m + 4 = 0

2 x^{2} - 8 x + 9

48 - x^{2} = 0

x, 36 x^{2} + 360 x + 64 y^{2} - 512 y + 1924 = 0

What are the solutions to the equation -2x^2+12x-10=0 ?
The solutions to the equation -2x^2+12x-10=0 are x=1,x=5
Find the zeros of -2x^2+12x-10=0
The zeros of -2x^2+12x-10=0 are x=1,x=5