What are the solutions to the equation m^2+10m+4=0 ?

The solutions to the equation m^2+10m+4=0 are m=-5+sqrt(21),m=-5-sqrt(21)

Find the zeros of m^2+10m+4=0

The zeros of m^2+10m+4=0 are m=-5+sqrt(21),m=-5-sqrt(21)

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m^{2} + 10 m + 4 = 0

m = - 5 + 21, m = - 5 - 21

Decimal Notation

m = - 0.41742 \dots, m = - 9.58257 \dots

Solution steps

m^{2} + 10 m + 4 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 4 = 221

m_{1, 2} = \frac{- 10 \pm 2 21}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 10 + 2 21}{2 \cdot 1}, m_{2} = \frac{- 10 - 2 21}{2 \cdot 1}

m = \frac{- 10 + 2 21}{2 \cdot 1} : - 5 + 21

m = \frac{- 10 - 2 21}{2 \cdot 1} : - 5 - 21

The solutions to the quadratic equation are:

m = - 5 + 21, m = - 5 - 21

2 x^{2} - 8 x + 9

48 - x^{2} = 0

x, 36 x^{2} + 360 x + 64 y^{2} - 512 y + 1924 = 0

64 x^{2} = - 49

11 = 10 x^{2} - x

What are the solutions to the equation m^2+10m+4=0 ?
The solutions to the equation m^2+10m+4=0 are m=-5+sqrt(21),m=-5-sqrt(21)
Find the zeros of m^2+10m+4=0
The zeros of m^2+10m+4=0 are m=-5+sqrt(21),m=-5-sqrt(21)